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Published on: August 14, 2026
XeF 4 reacts with SbF 5 to form [XeF m ] n+ [SbF m ] 2- m + n + y + z= ?
Text Solution
Verified by ExpertsThe correct answer is:
11
(11) Xenon tetrafluoride (XeF 4 ) is square planar and acts as a fluoride donor with SbF 5 . XeF 4 changes to the cation [XeF 3 ] + and SbF 5 changes to the anion [SbFe] - .
m = 3, n=l, y = 6, z = l
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